x(2x+1)=2x^2-4x+28

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Solution for x(2x+1)=2x^2-4x+28 equation: 


Simplifying
x(2x + 1) = 2x2 + -4x + 28

Reorder the terms:
x(1 + 2x) = 2x2 + -4x + 28
(1 * x + 2x * x) = 2x2 + -4x + 28
(1x + 2x2) = 2x2 + -4x + 28

Reorder the terms:
1x + 2x2 = 28 + -4x + 2x2

Add '-2x2' to each side of the equation.
1x + 2x2 + -2x2 = 28 + -4x + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
1x + 0 = 28 + -4x + 2x2 + -2x2
1x = 28 + -4x + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
1x = 28 + -4x + 0
1x = 28 + -4x

Solving
1x = 28 + -4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4x' to each side of the equation.
1x + 4x = 28 + -4x + 4x

Combine like terms: 1x + 4x = 5x
5x = 28 + -4x + 4x

Combine like terms: -4x + 4x = 0
5x = 28 + 0
5x = 28

Divide each side by '5'.
x = 5.6

Simplifying
x = 5.6

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